What are the solutions to the equation -x^2+16=0 ?

The solutions to the equation -x^2+16=0 are x=4,x=-4

Find the zeros of -x^2+16=0

The zeros of -x^2+16=0 are x=4,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} + 16 = 0

x = 4, x = - 4

Solution steps

- x^{2} + 16 = 0

Move

16

to the right side

- x^{2} = - 16

Divide both sides by

- 1

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

\frac{7}{12} + \frac{5}{8}

\frac{1}{3} - 2

5 x - 2 = 13

x - 6 = - 3 x + 22

(x^{2} + 3) = 4

What are the solutions to the equation -x^2+16=0 ?
The solutions to the equation -x^2+16=0 are x=4,x=-4
Find the zeros of -x^2+16=0
The zeros of -x^2+16=0 are x=4,x=-4