What is (x^3+6x^2-4x+7)-(3x^2+2x-4) ?

The solution to (x^3+6x^2-4x+7)-(3x^2+2x-4) is x^3+3x^2-6x+11

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simplify (x^3+6x^2-4x+7)-(3x^2+2x-4)

simplify

(x^{3} + 6 x^{2} - 4 x + 7) - (3 x^{2} + 2 x - 4)

x^{3} + 3 x^{2} - 6 x + 11

Solution steps

(x^{3} + 6 x^{2} - 4 x + 7) - (3 x^{2} + 2 x - 4)

Apply rule:

(a) = a

(x^{3} + 6 x^{2} - 4 x + 7) = x^{3} + 6 x^{2} - 4 x + 7

= x^{3} + 6 x^{2} - 4 x + 7 - (3 x^{2} + 2 x - 4)

Apply the distributive law:

- (a + b) = - a - b

- (3 x^{2} + 2 x - 4) = - 3 x^{2} - 2 x + 4

= x^{3} + 6 x^{2} - 4 x + 7 - 3 x^{2} - 2 x + 4

Group like terms

= x^{3} + 6 x^{2} - 3 x^{2} - 4 x - 2 x + 7 + 4

Add similar elements:

6 x^{2} - 3 x^{2} = 3 x^{2}

= x^{3} + 3 x^{2} - 4 x - 2 x + 7 + 4

Add similar elements:

- 4 x - 2 x = - 6 x

= x^{3} + 3 x^{2} - 6 x + 7 + 4

Add the numbers:

7 + 4 = 11

= x^{3} + 3 x^{2} - 6 x + 11

(3 i)^{2}

3 (x - 1) (x + 2)

\frac{1}{8} \cdot \frac{4}{5}

24 \cdot 3 \cdot 6

73 + 73

What is (x^3+6x^2-4x+7)-(3x^2+2x-4) ?
The solution to (x^3+6x^2-4x+7)-(3x^2+2x-4) is x^3+3x^2-6x+11