What is (3x^2+x+1)-(2x^2-3x-5) ?

The solution to (3x^2+x+1)-(2x^2-3x-5) is x^2+4x+6

Popular >

simplify (3x^2+x+1)-(2x^2-3x-5)

simplify

(3 x^{2} + x + 1) - (2 x^{2} - 3 x - 5)

x^{2} + 4 x + 6

Solution steps

(3 x^{2} + x + 1) - (2 x^{2} - 3 x - 5)

Apply rule:

(a) = a

(3 x^{2} + x + 1) = 3 x^{2} + x + 1

= 3 x^{2} + x + 1 - (2 x^{2} - 3 x - 5)

Apply the distributive law:

- (a - b) = - a + b

- (2 x^{2} - 3 x - 5) = - 2 x^{2} + 3 x + 5

= 3 x^{2} + x + 1 - 2 x^{2} + 3 x + 5

Group like terms

= 3 x^{2} - 2 x^{2} + x + 3 x + 1 + 5

Add similar elements:

3 x^{2} - 2 x^{2} = x^{2}

= x^{2} + x + 3 x + 1 + 5

Add similar elements:

x + 3 x = 4 x

= x^{2} + 4 x + 1 + 5

Add the numbers:

1 + 5 = 6

= x^{2} + 4 x + 6

2 a (a^{2} - 7) (a + 2)

\frac{3}{x - 3} - \frac{5}{x - 2}

\frac{x + 8}{x ^{2} + 13 x + 40} \cdot \frac{x ^{2} - 25}{9 x ^{2}}

lo g_{7} (98)

\frac{( 3 )}{( b - 3 )} + \frac{( b )}{( b - 3 )}

What is (3x^2+x+1)-(2x^2-3x-5) ?
The solution to (3x^2+x+1)-(2x^2-3x-5) is x^2+4x+6