What is expand (x-2)(x-3)(x-4)(x-5) ?

The solution to expand (x-2)(x-3)(x-4)(x-5) is x^4-14x^3+71x^2-154x+120

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expand (x-2)(x-3)(x-4)(x-5)

expand

(x - 2) (x - 3) (x - 4) (x - 5)

x^{4} - 14 x^{3} + 71 x^{2} - 154 x + 120

Solution steps

(x - 2) (x - 3) (x - 4) (x - 5)

Expand

(x - 2) (x - 3) (x - 4) (x - 5) : (x^{2} - 5 x + 6) (x - 4) (x - 5)

= (x^{2} - 5 x + 6) (x - 4) (x - 5)

Apply FOIL method

(x - 4) (x - 5) : x^{2} - 9 x + 20

= (x^{2} - 5 x + 6) (x^{2} - 9 x + 20)

Distribute parentheses

= x^{2} x^{2} + x^{2} (- 9 x) + x^{2} \cdot 20 - 5 x x^{2} - 5 x (- 9 x) - 5 x \cdot 20 + 6 x^{2} + 6 (- 9 x) + 6 \cdot 20

Simplify

x^{2} x^{2} + x^{2} (- 9 x) + x^{2} \cdot 20 - 5 x x^{2} - 5 x (- 9 x) - 5 x \cdot 20 + 6 x^{2} + 6 (- 9 x) + 6 \cdot 20 : x^{4} - 14 x^{3} + 71 x^{2} - 154 x + 120

= x^{4} - 14 x^{3} + 71 x^{2} - 154 x + 120

15 - 4 (\frac{3}{2} x + 8)

(x^{2} - 3 x + 2)^{2}

(\frac{3}{4} x^{2} y - \frac{1}{3} x z)^{2}

\frac{3}{4} \cdot \frac{2}{4}

2 0^{\circ} - 2 0^{g} + \frac{3}{8} π

What is expand (x-2)(x-3)(x-4)(x-5) ?
The solution to expand (x-2)(x-3)(x-4)(x-5) is x^4-14x^3+71x^2-154x+120