What is (x^2)/2+(2x^3)/3-(x^4)/4+x^5 ?

The solution to (x^2)/2+(2x^3)/3-(x^4)/4+x^5 is (12x^5+6x^2+8x^3-3x^4)/(12)

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simplify (x^2)/2+(2x^3)/3-(x^4)/4+x^5

simplify

\frac{x ^{2}}{2} + \frac{2 x ^{3}}{3} - \frac{x ^{4}}{4} + x^{5}

\frac{12 x ^{5} + 6 x ^{2} + 8 x ^{3} - 3 x ^{4}}{12}

Solution steps

\frac{x ^{2}}{2} + \frac{2 x ^{3}}{3} - \frac{x ^{4}}{4} + x^{5}

Join

\frac{x ^{2}}{2} + \frac{2 x ^{3}}{3} - \frac{x ^{4}}{4} + x^{5} : \frac{x ^{5} \cdot 12 + x ^{2} \cdot 6 + 8 x ^{3} - x ^{4} \cdot 3}{12}

= \frac{x ^{5} \cdot 12 + x ^{2} \cdot 6 + 8 x ^{3} - x ^{4} \cdot 3}{12}

= \frac{12 x ^{5} + 6 x ^{2} + 8 x ^{3} - 3 x ^{4}}{12}

(- 2 hk)^{4} (4 h^{3} k^{5})^{2}

8 (\frac{1}{4}) + 3 (\frac{1}{3})

(- 2 y + 5) (y + 3)

(a^{2} + b^{2} + c^{2})^{2}

What is (x^2)/2+(2x^3)/3-(x^4)/4+x^5 ?
The solution to (x^2)/2+(2x^3)/3-(x^4)/4+x^5 is (12x^5+6x^2+8x^3-3x^4)/(12)