What is (3/4 x^2+1/8 b^2)(3/4 x^2-1/8 b^2) ?

The solution to (3/4 x^2+1/8 b^2)(3/4 x^2-1/8 b^2) is ((3x^2)/4+(b^2)/8)((3x^2)/4-(b^2)/8)

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simplify (3/4 x^2+1/8 b^2)(3/4 x^2-1/8 b^2)

simplify

(\frac{3}{4} x^{2} + \frac{1}{8} b^{2}) (\frac{3}{4} x^{2} - \frac{1}{8} b^{2})

(\frac{3 x ^{2}}{4} + \frac{b ^{2}}{8}) (\frac{3 x ^{2}}{4} - \frac{b ^{2}}{8})

Solution steps

(\frac{3}{4} x^{2} + \frac{1}{8} b^{2}) (\frac{3}{4} x^{2} - \frac{1}{8} b^{2})

\frac{3}{4} x^{2} = \frac{3 x ^{2}}{4}

\frac{1}{8} b^{2} = \frac{b ^{2}}{8}

= (\frac{3 x ^{2}}{4} + \frac{b ^{2}}{8}) (\frac{3}{4} x^{2} - \frac{1}{8} b^{2})

\frac{3}{4} x^{2} = \frac{3 x ^{2}}{4}

\frac{1}{8} b^{2} = \frac{b ^{2}}{8}

= (\frac{3 x ^{2}}{4} + \frac{b ^{2}}{8}) (\frac{3 x ^{2}}{4} - \frac{b ^{2}}{8})

22 + 2

1 0^{2.1}

cos (x) cos (y) + sin (x) sin (y)

\frac{6 x ^{4} - 12 x ^{3} + 6 x ^{2}}{3 x ^{2}}

- \frac{1}{4} + \frac{3}{2}

What is (3/4 x^2+1/8 b^2)(3/4 x^2-1/8 b^2) ?
The solution to (3/4 x^2+1/8 b^2)(3/4 x^2-1/8 b^2) is ((3x^2)/4+(b^2)/8)((3x^2)/4-(b^2)/8)