What is (\frac{3y+2)/(3y)}{(6y^2+4y)/(3y+2)} ?

The solution to (\frac{3y+2)/(3y)}{(6y^2+4y)/(3y+2)} is (3y+2)/(6y^2)

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simplify (\frac{3y+2)/(3y)}{(6y^2+4y)/(3y+2)}

simplify

\frac{\frac{3 y + 2}{3 y}}{\frac{6 y ^{2} + 4 y}{3 y + 2}}

\frac{3 y + 2}{6 y ^{2}}

Solution steps

\frac{\frac{3 y + 2}{3 y}}{\frac{6 y ^{2} + 4 y}{3 y + 2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( 3 y + 2 ) ( 3 y + 2 )}{3 y ( 6 y ^{2} + 4 y )}

Cancel

\frac{( 3 y + 2 ) ( 3 y + 2 )}{3 y ( 6 y ^{2} + 4 y )} : \frac{3 y + 2}{6 y ^{2}}

= \frac{3 y + 2}{6 y ^{2}}

(\frac{x ^{2} + 4 x}{2 x + 6}) (\frac{2 x + 4}{x + 4})

- \frac{1}{x} - 1

\frac{a ^{3} b ^{- 5} c ^{- 1}}{c ^{- 4} b a ^{- 4}}

\frac{2}{6} + \frac{1}{7}

x^{3} + 4 x^{2} + 6 x + 4

What is (\frac{3y+2)/(3y)}{(6y^2+4y)/(3y+2)} ?
The solution to (\frac{3y+2)/(3y)}{(6y^2+4y)/(3y+2)} is (3y+2)/(6y^2)