What is ((x^3+3x^2-4x-12))/((x^2+5x+6)) ?

The solution to ((x^3+3x^2-4x-12))/((x^2+5x+6)) is x-2

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simplify ((x^3+3x^2-4x-12))/((x^2+5x+6))

simplify

\frac{( x ^{3} + 3 x ^{2} - 4 x - 12 )}{( x ^{2} + 5 x + 6 )}

x - 2

Solution steps

\frac{x ^{3} + 3 x ^{2} - 4 x - 12}{x ^{2} + 5 x + 6}

Factor

x^{3} + 3 x^{2} - 4 x - 12 : (x + 3) (x + 2) (x - 2)

= \frac{( x + 3 ) ( x + 2 ) ( x - 2 )}{x ^{2} + 5 x + 6}

Factor

x^{2} + 5 x + 6 : (x + 2) (x + 3)

= \frac{( x + 3 ) ( x + 2 ) ( x - 2 )}{( x + 2 ) ( x + 3 )}

Cancel the common factor:

x + 3

= \frac{( x + 2 ) ( x - 2 )}{x + 2}

Cancel the common factor:

x + 2

= x - 2

12 \cdot (- 5)

(7 - 3 i) (6 + i)

\frac{7}{3 s + 6} \cdot \frac{s + 2}{21}

\frac{51}{17}

\frac{n ^{4}}{n ^{6}}

What is ((x^3+3x^2-4x-12))/((x^2+5x+6)) ?
The solution to ((x^3+3x^2-4x-12))/((x^2+5x+6)) is x-2