What are the solutions to the equation 7x^2+2x=0 ?

The solutions to the equation 7x^2+2x=0 are x=0,x=-2/7

Find the zeros of 7x^2+2x=0

The zeros of 7x^2+2x=0 are x=0,x=-2/7

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7 x^{2} + 2 x = 0

x = 0, x = - \frac{2}{7}

Solution steps

7 x^{2} + 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 7 \cdot 0}{2 \cdot 7}

2^{2} - 4 \cdot 7 \cdot 0 = 2

x_{1, 2} = \frac{- 2 \pm 2}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 2 + 2}{2 \cdot 7}, x_{2} = \frac{- 2 - 2}{2 \cdot 7}

x = \frac{- 2 + 2}{2 \cdot 7} : 0

x = \frac{- 2 - 2}{2 \cdot 7} : - \frac{2}{7}

The solutions to the quadratic equation are:

x = 0, x = - \frac{2}{7}

x - 5 < 0

(- \frac{2 x}{3 y}) (- 5 x y)

- 4 x + 14 > 6 and 3 x + 5 > 17

4 x^{2} + 5 x + \frac{13}{8} = 0

6 x < - 10

What are the solutions to the equation 7x^2+2x=0 ?
The solutions to the equation 7x^2+2x=0 are x=0,x=-2/7
Find the zeros of 7x^2+2x=0
The zeros of 7x^2+2x=0 are x=0,x=-2/7