What are the solutions to the equation 4m^2+4m+1=0 ?

The solutions to the equation 4m^2+4m+1=0 are m=-1/2

Find the zeros of 4m^2+4m+1=0

The zeros of 4m^2+4m+1=0 are m=-1/2

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4 m^{2} + 4 m + 1 = 0

m = - \frac{1}{2}

Decimal Notation

m = - 0.5

Solution steps

4 m^{2} + 4 m + 1 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

m_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

m = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

m = - \frac{1}{2}

The solution to the quadratic equation is:

m = - \frac{1}{2}

(2 + 3)^{2} - (2 - 3)^{2}

121 = 64 x^{2}

4 y^{2} = 16 y + 3

6 - 2 x - x^{2} = x + 6

2 x^{2} - 4 < 0

What are the solutions to the equation 4m^2+4m+1=0 ?
The solutions to the equation 4m^2+4m+1=0 are m=-1/2
Find the zeros of 4m^2+4m+1=0
The zeros of 4m^2+4m+1=0 are m=-1/2