What is factor z^4-z^3+7z^2-9z-18 ?

The solution to factor z^4-z^3+7z^2-9z-18 is (z+1)(z-2)(z^2+9)

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factor z^4-z^3+7z^2-9z-18

factor

z^{4} - z^{3} + 7 z^{2} - 9 z - 18

(z + 1) (z - 2) (z^{2} + 9)

Solution steps

z^{4} - z^{3} + 7 z^{2} - 9 z - 18

Use the rational root theorem

= (z + 1) \frac{z ^{4} - z ^{3} + 7 z ^{2} - 9 z - 18}{z + 1}

\frac{z ^{4} - z ^{3} + 7 z ^{2} - 9 z - 18}{z + 1} = z^{3} - 2 z^{2} + 9 z - 18

= (z + 1) (z^{3} - 2 z^{2} + 9 z - 18)

Factor

z^{3} - 2 z^{2} + 9 z - 18 : (z - 2) (z^{2} + 9)

= (z + 1) (z - 2) (z^{2} + 9)

3 x^{3} - 4 x^{2} + 4 x - 1

8 1^{8^{- 9^{- 2^{- 1}}}}

\frac{1}{2} lo g_{2} (\frac{1}{2}) + \frac{1}{2} lo g_{2} (\frac{1}{2})

s + \frac{1}{s}

9 x^{2} + 6 x - 12

What is factor z^4-z^3+7z^2-9z-18 ?
The solution to factor z^4-z^3+7z^2-9z-18 is (z+1)(z-2)(z^2+9)