What are the solutions to the equation 25p^2=10p-1 ?

The solutions to the equation 25p^2=10p-1 are p= 1/5

Find the zeros of 25p^2=10p-1

The zeros of 25p^2=10p-1 are p= 1/5

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25 p^{2} = 10 p - 1

p = \frac{1}{5}

Solution steps

25 p^{2} = 10 p - 1

Move

1

to the left side

25 p^{2} + 1 = 10 p

Move

10 p

to the left side

25 p^{2} + 1 - 10 p = 0

Write in the standard form

a x^{2} + b x + c = 0

25 p^{2} - 10 p + 1 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 25 \cdot 1}{2 \cdot 25}

(- 10)^{2} - 4 \cdot 25 \cdot 1 = 0

p_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 25}

p = \frac{- ( - 10 )}{2 \cdot 25}

\frac{- ( - 10 )}{2 \cdot 25} = \frac{1}{5}

p = \frac{1}{5}

The solution to the quadratic equation is:

p = \frac{1}{5}

x^{2} = - x^{2} + 4 x

10 \leq 8 - 2 x \leq 18

x^{2} + 5 x - 5 = 0

1.76 = \frac{x - 693366}{693366} \cdot 100

What are the solutions to the equation 25p^2=10p-1 ?
The solutions to the equation 25p^2=10p-1 are p= 1/5
Find the zeros of 25p^2=10p-1
The zeros of 25p^2=10p-1 are p= 1/5