What is (\frac{a^2-2ab+b^2)/(a^2-b^2)}{1/(a+b)} ?

The solution to (\frac{a^2-2ab+b^2)/(a^2-b^2)}{1/(a+b)} is a-b

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simplify (\frac{a^2-2ab+b^2)/(a^2-b^2)}{1/(a+b)}

simplify

\frac{\frac{a ^{2} - 2 ab + b ^{2}}{a ^{2} - b ^{2}}}{\frac{1}{a + b}}

a - b

Solution steps

\frac{\frac{a ^{2} - 2 ab + b ^{2}}{a ^{2} - b ^{2}}}{\frac{1}{a + b}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( a ^{2} - 2 ab + b ^{2} ) ( a + b )}{( a ^{2} - b ^{2} ) \cdot 1}

Apply rule:

a \cdot 1 = a

= \frac{( a ^{2} - 2 ab + b ^{2} ) ( a + b )}{a ^{2} - b ^{2}}

Cancel

\frac{( a ^{2} - 2 ab + b ^{2} ) ( a + b )}{a ^{2} - b ^{2}} : a - b

= a - b

\frac{4 + i}{- 3 + 2 i}

\frac{\frac{8 k}{24 k ^{2} - 40 k}}{\frac{1}{15 k - 25}}

- \frac{7}{2} \div 3

\frac{x ^{2} - 10 x + 25}{x - 5}

4 \frac{1}{2} + 4^{2} + 3^{2}

What is (\frac{a^2-2ab+b^2)/(a^2-b^2)}{1/(a+b)} ?
The solution to (\frac{a^2-2ab+b^2)/(a^2-b^2)}{1/(a+b)} is a-b