What is expand (x+1)(x+2)(x+3)-(x-2)(x+3) ?

The solution to expand (x+1)(x+2)(x+3)-(x-2)(x+3) is x^3+5x^2+10x+12

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expand (x+1)(x+2)(x+3)-(x-2)(x+3)

expand

(x + 1) (x + 2) (x + 3) - (x - 2) (x + 3)

x^{3} + 5 x^{2} + 10 x + 12

Solution steps

(x + 1) (x + 2) (x + 3) - (x - 2) (x + 3)

Expand

(x + 1) (x + 2) (x + 3) : x^{3} + 6 x^{2} + 11 x + 6

= x^{3} + 6 x^{2} + 11 x + 6 - (x - 2) (x + 3)

Expand

- (x - 2) (x + 3) : - x^{2} - x + 6

= x^{3} + 6 x^{2} + 11 x + 6 - x^{2} - x + 6

Simplify

x^{3} + 6 x^{2} + 11 x + 6 - x^{2} - x + 6 : x^{3} + 5 x^{2} + 10 x + 12

= x^{3} + 5 x^{2} + 10 x + 12

(0.2)^{- 1}

75 - 147 + 675 - 12

\frac{( 1 - 3 i ) \cdot ( 3 - i )}{- 2 - 2 i}

\frac{4 ^{\frac{3}{2}}}{\frac{3}{2}}

5 - 15

What is expand (x+1)(x+2)(x+3)-(x-2)(x+3) ?
The solution to expand (x+1)(x+2)(x+3)-(x-2)(x+3) is x^3+5x^2+10x+12