What is (x^2+2x-3)/(x^2-9)*(x-3)/(x^2-4x+3) ?

The solution to (x^2+2x-3)/(x^2-9)*(x-3)/(x^2-4x+3) is 1/(x-3)

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simplify (x^2+2x-3)/(x^2-9)*(x-3)/(x^2-4x+3)

simplify

\frac{x ^{2} + 2 x - 3}{x ^{2} - 9} \cdot \frac{x - 3}{x ^{2} - 4 x + 3}

\frac{1}{x - 3}

Solution steps

\frac{x ^{2} + 2 x - 3}{x ^{2} - 9} \cdot \frac{x - 3}{x ^{2} - 4 x + 3}

Cancel

\frac{x ^{2} + 2 x - 3}{x ^{2} - 9} : \frac{x - 1}{x - 3}

= \frac{x - 1}{x - 3} \cdot \frac{x - 3}{x ^{2} - 4 x + 3}

Cross-cancel common factor:

x - 3

= \frac{x - 1}{x ^{2} - 4 x + 3}

Factor

x^{2} - 4 x + 3 : (x - 1) (x - 3)

= \frac{x - 1}{( x - 1 ) ( x - 3 )}

Cancel the common factor:

x - 1

= \frac{1}{x - 3}

(\frac{5 a ^{2} b ^{- 8} c}{25 a b ^{0} c ^{6}})^{3}

\frac{21 x ^{4} - 14 x ^{3} - 28 x ^{2}}{7 x ^{2}}

4 x - 3 x^{2}

490 y^{5} w^{6}

\frac{5}{6} \cdot \frac{4}{15} - \frac{3}{5} \cdot \frac{20}{18}

What is (x^2+2x-3)/(x^2-9)*(x-3)/(x^2-4x+3) ?
The solution to (x^2+2x-3)/(x^2-9)*(x-3)/(x^2-4x+3) is 1/(x-3)