What are the solutions to the equation 3z^2+12z-20=5z ?

The solutions to the equation 3z^2+12z-20=5z are z= 5/3 ,z=-4

Find the zeros of 3z^2+12z-20=5z

The zeros of 3z^2+12z-20=5z are z= 5/3 ,z=-4

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3 z^{2} + 12 z - 20 = 5 z

z = \frac{5}{3}, z = - 4

Decimal Notation

z = 1.66666 \dots, z = - 4

Solution steps

3 z^{2} + 12 z - 20 = 5 z

Move

5 z

to the left side

3 z^{2} + 7 z - 20 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 20 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 20) = 17

z_{1, 2} = \frac{- 7 \pm 17}{2 \cdot 3}

Separate the solutions

z_{1} = \frac{- 7 + 17}{2 \cdot 3}, z_{2} = \frac{- 7 - 17}{2 \cdot 3}

z = \frac{- 7 + 17}{2 \cdot 3} : \frac{5}{3}

z = \frac{- 7 - 17}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

z = \frac{5}{3}, z = - 4

\frac{2 ^{- 3}}{2 ^{- 5}}

2 x^{- \frac{1}{2}}

r^{2} - 3 r - 40 = 0

x - 9 \leq 2 (9 - x)

1 - 6 x + 9 x^{2} - 4 y^{2}

What are the solutions to the equation 3z^2+12z-20=5z ?
The solutions to the equation 3z^2+12z-20=5z are z= 5/3 ,z=-4
Find the zeros of 3z^2+12z-20=5z
The zeros of 3z^2+12z-20=5z are z= 5/3 ,z=-4