What is factor 1-6x+9x^2-4y^2 ?

The solution to factor 1-6x+9x^2-4y^2 is (3x-1+2y)(3x-1-2y)

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factor 1-6x+9x^2-4y^2

factor

1 - 6 x + 9 x^{2} - 4 y^{2}

(3 x - 1 + 2 y) (3 x - 1 - 2 y)

Solution steps

1 - 6 x + 9 x^{2} - 4 y^{2}

Factor

1 - 6 x + 9 x^{2} : (3 x - 1)^{2}

= (3 x - 1)^{2} - 4 y^{2}

Simplify

4 y^{2} : (2 y)^{2}

= (3 x - 1)^{2} - (2 y)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(3 x - 1)^{2} - (2 y)^{2} = ((3 x - 1) + 2 y) ((3 x - 1) - 2 y)

= ((3 x - 1) + 2 y) ((3 x - 1) - 2 y)

Apply rule:

(a) = a

(3 x - 1) = 3 x - 1

= (3 x - 1 + 2 y) (3 x - 1 - 2 y)

\frac{m - 2}{3} < - 2 or 4 m + 3 > 15

45 x^{2} - 8 x y - 4 y^{2}

2 r^{2} + r - 4 = 0

m^{2} + 5 m - 14 = 0

∣ x - 5 ∣ > 7

What is factor 1-6x+9x^2-4y^2 ?
The solution to factor 1-6x+9x^2-4y^2 is (3x-1+2y)(3x-1-2y)