What is (2x+8)/(x^2+6x+8)+1/(x+2) ?

The solution to (2x+8)/(x^2+6x+8)+1/(x+2) is 3/(x+2)

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simplify (2x+8)/(x^2+6x+8)+1/(x+2)

simplify

\frac{2 x + 8}{x ^{2} + 6 x + 8} + \frac{1}{x + 2}

\frac{3}{x + 2}

Solution steps

\frac{2 x + 8}{x ^{2} + 6 x + 8} + \frac{1}{x + 2}

Cancel

\frac{2 x + 8}{x ^{2} + 6 x + 8} : \frac{2}{x + 2}

= \frac{2}{x + 2} + \frac{1}{x + 2}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{2 + 1}{x + 2}

Add the numbers:

2 + 1 = 3

= \frac{3}{x + 2}

4 \cdot 4 \cdot 3

(- 5) - (- 3)

10 + \frac{1}{5}

lo g_{10} ((\frac{7}{8})^{x})

a^{3} + 8 b^{3}

What is (2x+8)/(x^2+6x+8)+1/(x+2) ?
The solution to (2x+8)/(x^2+6x+8)+1/(x+2) is 3/(x+2)