What is \sqrt[3]{(x+3)(x-3)(x-5)(x+1)+3} ?

The solution to \sqrt[3]{(x+3)(x-3)(x-5)(x+1)+3} is cube root of x^4-4x^3-14x^2+36x+48

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simplify \sqrt[3]{(x+3)(x-3)(x-5)(x+1)+3}

simplify

Solution steps

Expand

(x + 3) (x - 3) (x - 5) (x + 1) : x^{4} - 4 x^{3} - 14 x^{2} + 36 x + 45

Add the numbers:

45 + 3 = 48

ln (e^{8}) - 7 ln (e^{3})

0.4 - 1.96 \cdot \frac{0.4 \cdot 0.6}{600}

\frac{2 π}{4.71}

\frac{π}{4} + \frac{1}{2}

(- 32 x^{10} y^{35})^{- \frac{1}{5}}

What is \sqrt[3]{(x+3)(x-3)(x-5)(x+1)+3} ?
The solution to \sqrt[3]{(x+3)(x-3)(x-5)(x+1)+3} is cube root of x^4-4x^3-14x^2+36x+48