What is 1/3 log_{2}(8)+1/2 log_{2}(4) ?

The solution to 1/3 log_{2}(8)+1/2 log_{2}(4) is 2

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simplify 1/3 log_{2}(8)+1/2 log_{2}(4)

simplify

\frac{1}{3} lo g_{2} (8) + \frac{1}{2} lo g_{2} (4)

2

Solution steps

\frac{1}{3} lo g_{2} (8) + \frac{1}{2} lo g_{2} (4)

\frac{1}{3} lo g_{2} (8) = 1

\frac{1}{2} lo g_{2} (4) = 1

= 1 + 1

Add the numbers:

1 + 1 = 2

= 2

lo g_{0.25} (4)

\frac{1}{t} - \frac{1}{t ^{2} + t}

∣ a + b ∣^{2} - ∣ a - b ∣^{2}

32 y^{5} - 1

(\frac{x y ^{- 1}}{2 x ^{2} y ^{- 2}})^{- 3}

What is 1/3 log_{2}(8)+1/2 log_{2}(4) ?
The solution to 1/3 log_{2}(8)+1/2 log_{2}(4) is 2