What is expand (x+3)(x-2)(x-1) ?

The solution to expand (x+3)(x-2)(x-1) is x^3-7x+6

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expand (x+3)(x-2)(x-1)

expand

(x + 3) (x - 2) (x - 1)

x^{3} - 7 x + 6

Solution steps

(x + 3) (x - 2) (x - 1)

Expand

(x + 3) (x - 2) (x - 1) : (x^{2} + x - 6) (x - 1)

= (x^{2} + x - 6) (x - 1)

Distribute parentheses

= x^{2} x + x^{2} (- 1) + xx + x (- 1) - 6 x - 6 (- 1)

Simplify

x^{2} x + x^{2} (- 1) + xx + x (- 1) - 6 x - 6 (- 1) : x^{3} - 7 x + 6

= x^{3} - 7 x + 6

\frac{x ^{2} - 4 x + 3}{x ^{2} + 3 x - 4}

(r + 6)^{2} + (14 r - 11 + r^{2})

\frac{4}{5} \cdot 100

(4 x + 3)^{2}

\frac{4}{5} \div \frac{3}{5}

What is expand (x+3)(x-2)(x-1) ?
The solution to expand (x+3)(x-2)(x-1) is x^3-7x+6