What is (2x^2+1)-(x^2-2x+1) ?

The solution to (2x^2+1)-(x^2-2x+1) is x^2+2x

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simplify (2x^2+1)-(x^2-2x+1)

simplify

(2 x^{2} + 1) - (x^{2} - 2 x + 1)

x^{2} + 2 x

Solution steps

(2 x^{2} + 1) - (x^{2} - 2 x + 1)

Apply rule:

(a) = a

(2 x^{2} + 1) = 2 x^{2} + 1

= 2 x^{2} + 1 - (x^{2} - 2 x + 1)

Apply the distributive law:

- (a - b) = - a + b

- (x^{2} - 2 x + 1) = - x^{2} + 2 x - 1

= 2 x^{2} + 1 - x^{2} + 2 x - 1

Group like terms

= 2 x^{2} - x^{2} + 2 x + 1 - 1

Add similar elements:

2 x^{2} - x^{2} = x^{2}

= x^{2} + 2 x + 1 - 1

Subtract the numbers:

1 - 1 = 0

= x^{2} + 2 x

\frac{\frac{6 x + 6}{7}}{\frac{4 x + 4}{x - 2}}

\frac{1}{16} \cdot \frac{1}{2}

72 \cdot (- 0.0673)

(2 - 6 i) (7 + i)

2 3^{0}