What is x+8>= 9\land x/7 <= 1 ?

The solution to x+8>= 9\land x/7 <= 1 is 1<= x<= 7

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x+8>= 9\land x/7 <= 1

x + 8 \geq 9 and \frac{x}{7} \leq 1

1 \leq x \leq 7

Solution steps

x + 8 \geq 9 and \frac{x}{7} \leq 1

x + 8 \geq 9 : x \geq 1

\frac{x}{7} \leq 1 : x \leq 7

Combine the intervals

x \geq 1 and x \leq 7

Merge Overlapping Intervals

1 \leq x \leq 7

(x + 8 y) (2 x - 5 b) - 8 y (2 x - 5 b)

x^{2} + 12 = 10 x

m^{3} - 4 m

b^{2} - 4 b + 4

4 x + 7 - 15

What is x+8>= 9\land x/7 <= 1 ?
The solution to x+8>= 9\land x/7 <= 1 is 1<= x<= 7