What are the solutions to the equation x^2+12=10x ?

The solutions to the equation x^2+12=10x are x=5+sqrt(13),x=5-sqrt(13)

Find the zeros of x^2+12=10x

The zeros of x^2+12=10x are x=5+sqrt(13),x=5-sqrt(13)

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x^{2} + 12 = 10 x

x = 5 + 13, x = 5 - 13

Solution steps

x^{2} + 12 = 10 x

Move

10 x

to the left side

x^{2} + 12 - 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 10 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 12 = 213

x_{1, 2} = \frac{- ( - 10 ) \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 13}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 13}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 13}{2 \cdot 1} : 5 + 13

x = \frac{- ( - 10 ) - 2 13}{2 \cdot 1} : 5 - 13

The solutions to the quadratic equation are:

x = 5 + 13, x = 5 - 13

m^{3} - 4 m

b^{2} - 4 b + 4

4 x + 7 - 15

8 + (x + 3)^{2} = 0

- 3 (\frac{1}{2})

What are the solutions to the equation x^2+12=10x ?
The solutions to the equation x^2+12=10x are x=5+sqrt(13),x=5-sqrt(13)
Find the zeros of x^2+12=10x
The zeros of x^2+12=10x are x=5+sqrt(13),x=5-sqrt(13)