What is (10(c^2d^{-8})^3)/(2c^{-1)d^4} ?

The solution to (10(c^2d^{-8})^3)/(2c^{-1)d^4} is (5c^7)/(d^{28)}

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simplify (10(c^2d^{-8})^3)/(2c^{-1)d^4}

simplify

\frac{10 ( c ^{2} d ^{- 8} ) ^{3}}{2 c ^{- 1} d ^{4}}

\frac{5 c ^{7}}{d ^{28}}

Solution steps

\frac{10 ( c ^{2} d ^{- 8} ) ^{3}}{2 c ^{- 1} d ^{4}}

Factor the number:

10 = 2 \cdot 5

= \frac{2 \cdot 5 ( c ^{2} d ^{- 8} ) ^{3}}{2 c ^{- 1} d ^{4}}

Cancel the common factor:

2

= \frac{5 ( c ^{2} d ^{- 8} ) ^{3}}{c ^{- 1} d ^{4}}

Simplify

(c^{2} d^{- 8})^{3} : c^{6} \frac{1}{d ^{24}}

= \frac{5 c ^{6} \frac{1}{d ^{24}}}{c ^{- 1} d ^{4}}

Simplify

\frac{c ^{6}}{c ^{- 1}} : c^{7}

= \frac{5 c ^{7} \frac{1}{d ^{24}}}{d ^{4}}

Simplify

\frac{5 c ^{7} \frac{1}{d ^{24}}}{d ^{4}} : \frac{5 c ^{7}}{d ^{28}}

= \frac{5 c ^{7}}{d ^{28}}

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What is (10(c^2d^{-8})^3)/(2c^{-1)d^4} ?
The solution to (10(c^2d^{-8})^3)/(2c^{-1)d^4} is (5c^7)/(d^{28)}