What are the solutions to the equation -x^2+8x-19=0 ?

The solutions to the equation -x^2+8x-19=0 are x=4-sqrt(3)i,x=4+sqrt(3)i

Find the zeros of -x^2+8x-19=0

The zeros of -x^2+8x-19=0 are x=4-sqrt(3)i,x=4+sqrt(3)i

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- x^{2} + 8 x - 19 = 0

x = 4 - 3 i, x = 4 + 3 i

Solution steps

- x^{2} + 8 x - 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) ( - 19 )}{2 ( - 1 )}

Simplify

8^{2} - 4 (- 1) (- 19) : 23 i

x_{1, 2} = \frac{- 8 \pm 2 3 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 3 i}{2 ( - 1 )}, x_{2} = \frac{- 8 - 2 3 i}{2 ( - 1 )}

x = \frac{- 8 + 2 3 i}{2 ( - 1 )} : 4 - 3 i

x = \frac{- 8 - 2 3 i}{2 ( - 1 )} : 4 + 3 i

The solutions to the quadratic equation are:

x = 4 - 3 i, x = 4 + 3 i

u^{2} + u - 20 = 0

x^{2} + 14 + 24

C - 12 = - 24

4 + \frac{x + 5}{8} = 20

12 x^{2} - 22 x - 20

What are the solutions to the equation -x^2+8x-19=0 ?
The solutions to the equation -x^2+8x-19=0 are x=4-sqrt(3)i,x=4+sqrt(3)i
Find the zeros of -x^2+8x-19=0
The zeros of -x^2+8x-19=0 are x=4-sqrt(3)i,x=4+sqrt(3)i