What is (2^3a^{-3})/(8^{-1)b^{-5}c^0} ?

The solution to (2^3a^{-3})/(8^{-1)b^{-5}c^0} is (64b^5)/(a^3)

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simplify (2^3a^{-3})/(8^{-1)b^{-5}c^0}

simplify

\frac{2 ^{3} a ^{- 3}}{8 ^{- 1} b ^{- 5} c ^{0}}

\frac{64 b ^{5}}{a ^{3}}

Solution steps

\frac{2 ^{3} a ^{- 3}}{8 ^{- 1} b ^{- 5} c ^{0}}

Simplify

\frac{2 ^{3} a ^{- 3}}{8 ^{- 1} b ^{- 5} c ^{0}} : \frac{2 ^{3} a ^{- 3}}{8 ^{- 1} b ^{- 5}}

= \frac{2 ^{3} a ^{- 3}}{8 ^{- 1} b ^{- 5}}

Cancel

\frac{2 ^{3} a ^{- 3}}{8 ^{- 1} b ^{- 5}} : \frac{2 ^{6} a ^{- 3}}{b ^{- 5}}

= \frac{2 ^{6} a ^{- 3}}{b ^{- 5}}

Simplify

\frac{2 ^{6} a ^{- 3}}{b ^{- 5}} : \frac{64 b ^{5}}{a ^{3}}

= \frac{64 b ^{5}}{a ^{3}}

\frac{1}{\frac{8}{3}}

y^{2} - y - 20 = 0

\frac{\frac{1}{2}}{- \frac{3}{2}}

x^{2} \leq 6 x - 4

(4)^{2}

What is (2^3a^{-3})/(8^{-1)b^{-5}c^0} ?
The solution to (2^3a^{-3})/(8^{-1)b^{-5}c^0} is (64b^5)/(a^3)