What is expand (3^{(n+1)(n+2)}+65)/(72) ?

The solution to expand (3^{(n+1)(n+2)}+65)/(72) is (3^{n^2+3n})/8+65/72

Popular >

expand (3^{(n+1)(n+2)}+65)/(72)

expand

\frac{3 ^{(n + 1) (n + 2)} + 65}{72}

\frac{3 ^{n^{2} + 3 n}}{8} + \frac{65}{72}

Solution steps

\frac{3 ^{(n + 1) (n + 2)} + 65}{72}

Expand

(n + 1) (n + 2) : n^{2} + 3 n + 2

= \frac{3 ^{n^{2} + 3 n + 2} + 65}{72}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 ^{n^{2} + 3 n + 2} + 65}{72} = \frac{3 ^{n^{2} + 3 n + 2}}{72} + \frac{65}{72}

= \frac{3 ^{n^{2} + 3 n + 2}}{72} + \frac{65}{72}

\frac{3 ^{n^{2} + 3 n + 2}}{72} = \frac{3 ^{n^{2} + 3 n}}{8}

= \frac{3 ^{n^{2} + 3 n}}{8} + \frac{65}{72}

(1 - e^{- a t}) sin (x)

\frac{( x - 1 ) ^{4 n} ( x ^{3} + 8 ) ( x - 4 )}{( x ^{2} - 2 x + 2 )}

A B + A (C D + C D^{^{'}})

A (1, 3) B (2, - 5)

(3 e^{3 t} + 4 e^{- 4 t})^{3}

What is expand (3^{(n+1)(n+2)}+65)/(72) ?
The solution to expand (3^{(n+1)(n+2)}+65)/(72) is (3^{n^2+3n})/8+65/72