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Popular >

expand ((2x-3)^2)/3

Solution

expand

\frac{( 2 x - 3 ) ^{2}}{3}

Solution

\frac{4 x ^{2}}{3} - 4 x + 3

Solution steps

\frac{( 2 x - 3 ) ^{2}}{3}

(2 x - 3)^{2} = 4 x^{2} - 12 x + 9

= \frac{4 x ^{2} - 12 x + 9}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{2} - 12 x + 9}{3} = \frac{4 x ^{2}}{3} - \frac{12 x}{3} + \frac{9}{3}

= \frac{4 x ^{2}}{3} - \frac{12 x}{3} + \frac{9}{3}

Divide the numbers:

\frac{12}{3} = 4

= \frac{4 x ^{2}}{3} - 4 x + \frac{9}{3}

Divide the numbers:

\frac{9}{3} = 3

= \frac{4 x ^{2}}{3} - 4 x + 3

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Frequently Asked Questions (FAQ)

What is expand ((2x-3)^2)/3 ?
The solution to expand ((2x-3)^2)/3 is (4x^2)/3-4x+3