What is (1+2/(c-1))/(1-2/(c-1)) ?

The solution to (1+2/(c-1))/(1-2/(c-1)) is (c+1)/(c-3)

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simplify (1+2/(c-1))/(1-2/(c-1))

simplify

\frac{1 + \frac{2}{c - 1}}{1 - \frac{2}{c - 1}}

\frac{c + 1}{c - 3}

Solution steps

\frac{1 + \frac{2}{c - 1}}{1 - \frac{2}{c - 1}}

Join

1 + \frac{2}{c - 1} : \frac{c + 1}{c - 1}

= \frac{\frac{c + 1}{c - 1}}{1 - \frac{2}{c - 1}}

Join

1 - \frac{2}{c - 1} : \frac{c - 3}{c - 1}

= \frac{\frac{c + 1}{c - 1}}{\frac{c - 3}{c - 1}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( c + 1 ) ( c - 1 )}{( c - 1 ) ( c - 3 )}

Cancel the common factor:

c - 1

= \frac{c + 1}{c - 3}

x^{2} - 35 x + 300 = 0

- \frac{5}{8} + \frac{1}{2}

4 ∣ x - 1 ∣ + 2 > 6

\frac{x ^{- 1}}{( x y ) ^{3}}

2.8 d^{2} - 0.44 d - 0.0484 = 0

What is (1+2/(c-1))/(1-2/(c-1)) ?
The solution to (1+2/(c-1))/(1-2/(c-1)) is (c+1)/(c-3)