What is expand ((x^3-11x^2+25x-20)13)/(10) ?

The solution to expand ((x^3-11x^2+25x-20)13)/(10) is (13x^3}{10}-(143x^2)/(10)+\frac{65x)/2-26

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((x^3-11x^2+25x-20)13)/(10)

expand

\frac{( x ^{3} - 11 x ^{2} + 25 x - 20 ) 13}{10}

\frac{13 x ^{3}}{10} - \frac{143 x ^{2}}{10} + \frac{65 x}{2} - 26

Solution steps

\frac{( x ^{3} - 11 x ^{2} + 25 x - 20 ) \cdot 13}{10}

Expand

(x^{3} - 11 x^{2} + 25 x - 20) \cdot 13 : 13 x^{3} - 143 x^{2} + 325 x - 260

= \frac{13 x ^{3} - 143 x ^{2} + 325 x - 260}{10}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{13 x ^{3} - 143 x ^{2} + 325 x - 260}{10} = \frac{13 x ^{3}}{10} - \frac{143 x ^{2}}{10} + \frac{325 x}{10} - \frac{260}{10}

= \frac{13 x ^{3}}{10} - \frac{143 x ^{2}}{10} + \frac{325 x}{10} - \frac{260}{10}

Cancel

\frac{325 x}{10} : \frac{65 x}{2}

= \frac{13 x ^{3}}{10} - \frac{143 x ^{2}}{10} + \frac{65 x}{2} - \frac{260}{10}

Divide the numbers:

\frac{260}{10} = 26

= \frac{13 x ^{3}}{10} - \frac{143 x ^{2}}{10} + \frac{65 x}{2} - 26

\frac{( c + 5 ) ( c - 4 )}{2 ( c + 2 )}

\frac{( 7 ( x - 3 ) )}{4}

\frac{1}{( s - 2 ) ( s ^{2} + 3 )}

\frac{2 x ^{2} + 3}{( x ^{2} + 1 ) ^{2}}

\frac{( 3 x + 4 ) ^{3}}{9}

What is expand ((x^3-11x^2+25x-20)13)/(10) ?
The solution to expand ((x^3-11x^2+25x-20)13)/(10) is (13x^3}{10}-(143x^2)/(10)+\frac{65x)/2-26