What is expand (4(x+2)(x-1))/((x^2+2x+2)^2) ?

The solution to expand (4(x+2)(x-1))/((x^2+2x+2)^2) is (4x^2+4x-8)/(x^4+4x^3+8x^2+8x+4)

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expand (4(x+2)(x-1))/((x^2+2x+2)^2)

expand

\frac{4 ( x + 2 ) ( x - 1 )}{( x ^{2} + 2 x + 2 ) ^{2}}

\frac{4 x ^{2} + 4 x - 8}{x ^{4} + 4 x ^{3} + 8 x ^{2} + 8 x + 4}

Solution steps

\frac{4 ( x + 2 ) ( x - 1 )}{( x ^{2} + 2 x + 2 ) ^{2}}

(x^{2} + 2 x + 2)^{2} = x^{4} + 4 x^{3} + 8 x^{2} + 8 x + 4

= \frac{4 ( x + 2 ) ( x - 1 )}{x ^{4} + 4 x ^{3} + 8 x ^{2} + 8 x + 4}

Expand

4 (x + 2) (x - 1) : 4 x^{2} + 4 x - 8

= \frac{4 x ^{2} + 4 x - 8}{x ^{4} + 4 x ^{3} + 8 x ^{2} + 8 x + 4}

\frac{8}{s ^{3} ( s ^{2} - s - 2 )}

\frac{x}{( x ^{2} + 4 ) ( x - 3 )}

\frac{( 1 + 2 x ) ^{4}}{4}

\frac{1}{x f ( x ^{2} - 5 x )}

3 (x^{6})

What is expand (4(x+2)(x-1))/((x^2+2x+2)^2) ?
The solution to expand (4(x+2)(x-1))/((x^2+2x+2)^2) is (4x^2+4x-8)/(x^4+4x^3+8x^2+8x+4)