What is expand (2x-1)/((x-4)^2) ?

The solution to expand (2x-1)/((x-4)^2) is (2x-1)/(x^2-8x+16)

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expand (2x-1)/((x-4)^2)

expand

\frac{2 x - 1}{( x - 4 ) ^{2}}

\frac{2 x - 1}{x ^{2} - 8 x + 16}

Solution steps

\frac{2 x - 1}{( x - 4 ) ^{2}}

(x - 4)^{2} = x^{2} - 8 x + 16

= \frac{2 x - 1}{x ^{2} - 8 x + 16}

\frac{x ^{2} + 2 x + 2}{2 ( x + 2 )}

\frac{( 2 x - 1 ) ( x + 2 )}{2}

(- 1, 5) y (2, - 1)

\frac{x ^{2} - 2 x + k - 2}{( x - 1 ) ^{2} ( x + 2 )}

x + 1 + (x + 1) e^{- 2 x}

What is expand (2x-1)/((x-4)^2) ?
The solution to expand (2x-1)/((x-4)^2) is (2x-1)/(x^2-8x+16)