What is expand (2x^2-3)/((x^2+9)(x^2-4)) ?

The solution to expand (2x^2-3)/((x^2+9)(x^2-4)) is (2x^2-3)/(x^4+5x^2-36)

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expand (2x^2-3)/((x^2+9)(x^2-4))

expand

\frac{2 x ^{2} - 3}{( x ^{2} + 9 ) ( x ^{2} - 4 )}

\frac{2 x ^{2} - 3}{x ^{4} + 5 x ^{2} - 36}

Solution steps

\frac{2 x ^{2} - 3}{( x ^{2} + 9 ) ( x ^{2} - 4 )}

Expand

(x^{2} + 9) (x^{2} - 4) : x^{4} + 5 x^{2} - 36

= \frac{2 x ^{2} - 3}{x ^{4} + 5 x ^{2} - 36}

\frac{2 x ^{2} - 2}{( x ^{2} + 1 ) ^{2}}

[(x + 1)^{2} - 2 y] d x - (x^{2} - 1) d y

(5 f + 3 e)^{2}

\frac{( 1 + x ^{n} )}{( 1 + x ) ^{n}}

\frac{1}{( x - 3 ) ( x - 2 ) ( x - 1 )}

What is expand (2x^2-3)/((x^2+9)(x^2-4)) ?
The solution to expand (2x^2-3)/((x^2+9)(x^2-4)) is (2x^2-3)/(x^4+5x^2-36)