What is expand 2(2e^{-2x}+1/3 e^x) ?

The solution to expand 2(2e^{-2x}+1/3 e^x) is 4e^{-2x}+2/3 e^x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 2(2e^{-2x}+1/3 e^x)

expand

2 (2 e^{- 2 x} + \frac{1}{3} e^{x})

4 e^{- 2 x} + \frac{2}{3} e^{x}

Solution steps

2 (2 e^{- 2 x} + \frac{1}{3} e^{x})

Apply the distributive law:

a (b + c) = ab + a c

a = 2, b = 2 e^{- 2 x}, c = \frac{1}{3} e^{x}

= 2 \cdot 2 e^{- 2 x} + 2 \cdot \frac{1}{3} e^{x}

Simplify

2 \cdot 2 e^{- 2 x} + 2 \cdot \frac{1}{3} e^{x} : 4 e^{- 2 x} + \frac{2}{3} e^{x}

= 4 e^{- 2 x} + \frac{2}{3} e^{x}

\frac{2 x}{( x - 1 ) ( x + 1 )}

\frac{\partial}{\partial u} ((x) (a u + b v))

(1 - e^{- \frac{x}{8}})^{3}

\frac{1}{( s - 1 ) ( s + 2 ) ( s + 4 )}

\frac{k ( z + 0.5 )}{( z + 1 ) ( z - 0.5 ) ( z - 1 )}

What is expand 2(2e^{-2x}+1/3 e^x) ?
The solution to expand 2(2e^{-2x}+1/3 e^x) is 4e^{-2x}+2/3 e^x