What is expand 4sin(pi/2 (x-3))+8 ?

The solution to expand 4sin(pi/2 (x-3))+8 is 4cos((pix)/2)+8

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expand 4sin(pi/2 (x-3))+8

expand

4 sin (\frac{π}{2} (x - 3)) + 8

4 cos (\frac{π x}{2}) + 8

Solution steps

4 sin (\frac{π}{2} (x - 3)) + 8

4 sin (\frac{π}{2} (x - 3)) = 4 cos (\frac{π x}{2})

= 4 cos (\frac{π x}{2}) + 8

2 (t^{3} + 2 t + 4)^{2}

\frac{( 4 y ^{6} - 1 ) ^{2}}{16 y ^{6}}

\frac{x - 3}{( x + 3 ) ( x + 1 )}

2 (π - θ)

\frac{s ^{2} - s + 1}{( s + 1 ) ^{2}}

What is expand 4sin(pi/2 (x-3))+8 ?
The solution to expand 4sin(pi/2 (x-3))+8 is 4cos((pix)/2)+8