What is expand ((2-x^2)^2)/2 ?

The solution to expand ((2-x^2)^2)/2 is (x^4)/2-2x^2+2

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expand ((2-x^2)^2)/2

expand

\frac{( 2 - x ^{2} ) ^{2}}{2}

\frac{x ^{4}}{2} - 2 x^{2} + 2

Solution steps

\frac{( 2 - x ^{2} ) ^{2}}{2}

(2 - x^{2})^{2} = 4 - 4 x^{2} + x^{4}

= \frac{4 - 4 x ^{2} + x ^{4}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 - 4 x ^{2} + x ^{4}}{2} = \frac{4}{2} - \frac{4 x ^{2}}{2} + \frac{x ^{4}}{2}

= \frac{4}{2} - \frac{4 x ^{2}}{2} + \frac{x ^{4}}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2 - 2 x^{2} + \frac{x ^{4}}{2}

Rewrite in standard form

= \frac{x ^{4}}{2} - 2 x^{2} + 2

(y^{2} - x^{2}) d x + 2 x y d y

(1 + x + x^{2})^{8}

\frac{3 x - 1}{( x ^{2} - 1 ) ^{3}}

\frac{16 x y + 2 - x ^{2} y ^{2} - 28}{16 ( x ^{2} y ^{2} - 4 )}

Q (12, - 13)

What is expand ((2-x^2)^2)/2 ?
The solution to expand ((2-x^2)^2)/2 is (x^4)/2-2x^2+2