What is expand (2x^3-1)/((2x^4-4x)^3) ?

The solution to expand (2x^3-1)/((2x^4-4x)^3) is (2x^3-1)/(8x^{12)-48x^9+96x^6-64x^3}

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expand (2x^3-1)/((2x^4-4x)^3)

expand

\frac{2 x ^{3} - 1}{( 2 x ^{4} - 4 x ) ^{3}}

\frac{2 x ^{3} - 1}{8 x ^{12} - 48 x ^{9} + 96 x ^{6} - 64 x ^{3}}

Solution steps

\frac{2 x ^{3} - 1}{( 2 x ^{4} - 4 x ) ^{3}}

(2 x^{4} - 4 x)^{3} = 8 x^{12} - 48 x^{9} + 96 x^{6} - 64 x^{3}

= \frac{2 x ^{3} - 1}{8 x ^{12} - 48 x ^{9} + 96 x ^{6} - 64 x ^{3}}

\frac{( 3 - x ) ^{2}}{9}

A (- 2, - 3) B (1, 3)

- \frac{x ( - x + 1 ) ^{3}}{3}

\frac{1}{81} (e^{9 x} \cdot 9 x - e^{9 x})

What is expand (2x^3-1)/((2x^4-4x)^3) ?
The solution to expand (2x^3-1)/((2x^4-4x)^3) is (2x^3-1)/(8x^{12)-48x^9+96x^6-64x^3}