What is factor z^2b^2+zb-2 ?

The solution to factor z^2b^2+zb-2 is (zb-1)(zb+2)

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factor z^2b^2+zb-2

factor

z^{2} b^{2} + z b - 2

(z b - 1) (z b + 2)

Solution steps

z^{2} b^{2} + z b - 2

Break the expression into groups

= (z^{2} b^{2} - z b) + (2 z b - 2)

Factor out

z b

from

z^{2} b^{2} - z b : z b (z b - 1)

Factor out

2

from

2 z b - 2 : 2 (z b - 1)

= z b (z b - 1) + 2 (z b - 1)

Factor out common term

z b - 1

= (z b - 1) (z b + 2)

\frac{10 !}{4 ! 6 !}

\frac{2 x ^{2} y}{6 x y ^{- 1}}

(\frac{a}{b ^{2}})^{- 2} (\frac{a}{b ^{2}})^{- 3}

∣ x ∣ = 6.5

\frac{15}{12}