What is (a/(b^2))^{-2}(a/(b^2))^{-3} ?

The solution to (a/(b^2))^{-2}(a/(b^2))^{-3} is (b^{10})/(a^5)

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simplify (a/(b^2))^{-2}(a/(b^2))^{-3}

simplify

(\frac{a}{b ^{2}})^{- 2} (\frac{a}{b ^{2}})^{- 3}

\frac{b ^{10}}{a ^{5}}

Solution steps

(\frac{a}{b ^{2}})^{- 2} (\frac{a}{b ^{2}})^{- 3}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

(\frac{a}{b ^{2}})^{- 2} (\frac{a}{b ^{2}})^{- 3} = (\frac{a}{b ^{2}})^{- 2 - 3}

= (\frac{a}{b ^{2}})^{- 2 - 3}

Subtract the numbers:

- 2 - 3 = - 5

= (\frac{a}{b ^{2}})^{- 5}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{a}{b ^{2}})^{- 5} = \frac{1}{( \frac{a}{b ^{2}} ) ^{5}}

= \frac{1}{( \frac{a}{b ^{2}} ) ^{5}}

Simplify

(\frac{a}{b ^{2}})^{5} : \frac{a ^{5}}{b ^{10}}

= \frac{1}{\frac{a ^{5}}{b ^{10}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{b ^{10}}{a ^{5}}

∣ x ∣ = 6.5

\frac{15}{12}

- 10 - (- 5)

5 x^{2} - 4 x - 9 = - 9

\frac{1}{\frac{2}{5}}

What is (a/(b^2))^{-2}(a/(b^2))^{-3} ?
The solution to (a/(b^2))^{-2}(a/(b^2))^{-3} is (b^{10})/(a^5)