What is expand ((t^3)/3+1/(4t^2))dt ?

The solution to expand ((t^3)/3+1/(4t^2))dt is (t^3dt)/3+(dt)/(4t^2)

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expand ((t^3)/3+1/(4t^2))dt

expand

(\frac{t ^{3}}{3} + \frac{1}{4 t ^{2}}) d t

\frac{t ^{3} d t}{3} + \frac{d t}{4 t ^{2}}

Solution steps

(\frac{t ^{3}}{3} + \frac{1}{4 t ^{2}}) d t

Apply the distributive law:

a (b + c) = ab + a c

a = d t, b = \frac{t ^{3}}{3}, c = \frac{1}{4 t ^{2}}

= d t \frac{t ^{3}}{3} + d t \frac{1}{4 t ^{2}}

= \frac{t ^{3}}{3} d t + \frac{1}{4 t ^{2}} d t

Simplify

\frac{t ^{3}}{3} d t + \frac{1}{4 t ^{2}} d t : \frac{t ^{3} d t}{3} + \frac{d t}{4 t ^{2}}

= \frac{t ^{3} d t}{3} + \frac{d t}{4 t ^{2}}

(1 + e^{\frac{1}{x}})^{2}

1 + \frac{k}{( s + 1 ) ( s ^{2} + s + 1.5 )}

\frac{( ( x + 4 ) ( 6 a + x - 4 ) )}{6}

\frac{\partial}{\partial x} ((z) (z^{3} - 3 x yz))

\frac{1}{( x + 2 ) ( x + 1 )}

What is expand ((t^3)/3+1/(4t^2))dt ?
The solution to expand ((t^3)/3+1/(4t^2))dt is (t^3dt)/3+(dt)/(4t^2)