What is expand ((k-1)x^2+kx+1)/((x+3)) ?

The solution to expand ((k-1)x^2+kx+1)/((x+3)) is (kx^2-x^2+kx+1)/(x+3)

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expand ((k-1)x^2+kx+1)/((x+3))

expand

\frac{( k - 1 ) x ^{2} + k x + 1}{( x + 3 )}

\frac{k x ^{2} - x ^{2} + k x + 1}{x + 3}

Solution steps

\frac{( k - 1 ) x ^{2} + k x + 1}{x + 3}

Expand

(k - 1) x^{2} + k x + 1 : k x^{2} - x^{2} + k x + 1

= \frac{k x ^{2} - x ^{2} + k x + 1}{x + 3}

- 3 (x + y t) e^{- 3 t} + 2 (y) e^{- 3 t}

(e^{x} + 3) (sin (x) + ln (x))

\frac{x ( 4 x - 3 )}{2}

2 ab c (a + b + c)^{3}

\frac{( x - 1 ) ^{2}}{( x + 1 ) ( x + 2 )}

What is expand ((k-1)x^2+kx+1)/((x+3)) ?
The solution to expand ((k-1)x^2+kx+1)/((x+3)) is (kx^2-x^2+kx+1)/(x+3)