What is expand 2/((2s+1)(s+1)(s+2)) ?

The solution to expand 2/((2s+1)(s+1)(s+2)) is 2/(2s^3+7s^2+7s+2)

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expand 2/((2s+1)(s+1)(s+2))

expand

\frac{2}{( 2 s + 1 ) ( s + 1 ) ( s + 2 )}

\frac{2}{2 s ^{3} + 7 s ^{2} + 7 s + 2}

Solution steps

\frac{2}{( 2 s + 1 ) ( s + 1 ) ( s + 2 )}

Expand

(2 s + 1) (s + 1) (s + 2) : 2 s^{3} + 7 s^{2} + 7 s + 2

= \frac{2}{2 s ^{3} + 7 s ^{2} + 7 s + 2}

- (\frac{9}{14} lo g_{2} (\frac{9}{14}) + \frac{5}{14} lo g_{2} (\frac{5}{14}))

2 e^{x^{2} - 4 x} (2 x - 4)

- (3 x + 8 - (- 15 + 6 x - (- 3 x + 2) - (5 x + 4) - 29) = - 5)

cos (2 (t - 2 π))

3 c - 3

What is expand 2/((2s+1)(s+1)(s+2)) ?
The solution to expand 2/((2s+1)(s+1)(s+2)) is 2/(2s^3+7s^2+7s+2)