What is expand 1-(2x+1)e^{-2x} ?

The solution to expand 1-(2x+1)e^{-2x} is 1-2e^{-2x}x-e^{-2x}

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expand 1-(2x+1)e^{-2x}

expand

1 - (2 x + 1) e^{- 2 x}

1 - 2 e^{- 2 x} x - e^{- 2 x}

Solution steps

1 - (2 x + 1) e^{- 2 x}

= 1 - e^{- 2 x} (2 x + 1)

Expand

- e^{- 2 x} (2 x + 1) : - 2 e^{- 2 x} x - e^{- 2 x}

= 1 - 2 e^{- 2 x} x - e^{- 2 x}

2 (\frac{π}{6} - \frac{3}{4})

d x ((x - sin (x)) (x + cos (x)))

10 (k x)

e [3414 - 316 (ln (60)) - 316 (ln (60))^{2}]

x^{2} y^{'} (x) + (x + 1) y

What is expand 1-(2x+1)e^{-2x} ?
The solution to expand 1-(2x+1)e^{-2x} is 1-2e^{-2x}x-e^{-2x}