What is expand (4x)/((x+1)(x-3)) ?

The solution to expand (4x)/((x+1)(x-3)) is (4x)/(x^2-2x-3)

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expand (4x)/((x+1)(x-3))

expand

\frac{4 x}{( x + 1 ) ( x - 3 )}

\frac{4 x}{x ^{2} - 2 x - 3}

Solution steps

\frac{4 x}{( x + 1 ) ( x - 3 )}

Expand

(x + 1) (x - 3) : x^{2} - 2 x - 3

= \frac{4 x}{x ^{2} - 2 x - 3}

(3, 7) y (- 2, - 1)

sinh (x) H (x) - eH (x - 1) sinh (x - 1)

cosh (t + π) u (t + π)

\frac{( x + 12 ) ( x - 3 )}{( x + 12 ) 5 x}

[\frac{1}{( x + 1 ) ^{2}}]^{^{'}}

What is expand (4x)/((x+1)(x-3)) ?
The solution to expand (4x)/((x+1)(x-3)) is (4x)/(x^2-2x-3)