What is expand (e^{3t}-e^{2t})^2 ?

The solution to expand (e^{3t}-e^{2t})^2 is e^{6t}-2e^{5t}+e^{4t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (e^{3t}-e^{2t})^2

expand

(e^{3 t} - e^{2 t})^{2}

e^{6 t} - 2 e^{5 t} + e^{4 t}

Solution steps

(e^{3 t} - e^{2 t})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = e^{3 t}, b = e^{2 t}

= (e^{3 t})^{2} - 2 e^{3 t} e^{2 t} + (e^{2 t})^{2}

Simplify

(e^{3 t})^{2} - 2 e^{3 t} e^{2 t} + (e^{2 t})^{2} : e^{6 t} - 2 e^{5 t} + e^{4 t}

= e^{6 t} - 2 e^{5 t} + e^{4 t}

\frac{5}{2} cos (\frac{2 π}{365} (t - \frac{1067}{4})) + 12

\frac{x - 5}{( x - 2 ) ( x - 9 )}

\frac{10}{( s + 1 ) ( s + 3 ) ( s ^{2} + 2 s + 5 )}

(\frac{x - 1}{2 x})^{2}

\frac{6}{( s ^{2} - 4 s ) ( s - 3 )}

What is expand (e^{3t}-e^{2t})^2 ?
The solution to expand (e^{3t}-e^{2t})^2 is e^{6t}-2e^{5t}+e^{4t}