What is expand 6/((s^2-4s)(s-3)) ?

The solution to expand 6/((s^2-4s)(s-3)) is 6/(s^3-7s^2+12s)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 6/((s^2-4s)(s-3))

expand

\frac{6}{( s ^{2} - 4 s ) ( s - 3 )}

\frac{6}{s ^{3} - 7 s ^{2} + 12 s}

Solution steps

\frac{6}{( s ^{2} - 4 s ) ( s - 3 )}

Expand

(s^{2} - 4 s) (s - 3) : s^{3} - 7 s^{2} + 12 s

= \frac{6}{s ^{3} - 7 s ^{2} + 12 s}

(b^{2} e^{b x} sin (x) + b e^{b x} cos (x))^{2}

\frac{( 1 - x )}{( x + 2 ) ^{2}}

\frac{n ^{6}}{( n + 1 ) ^{6}}

\frac{\partial}{\partial y} (5 e^{y}) + e^{y} (4 x + 5 y)

4 (x + Δ x)^{3}

What is expand 6/((s^2-4s)(s-3)) ?
The solution to expand 6/((s^2-4s)(s-3)) is 6/(s^3-7s^2+12s)