What is expand-sin((k+1/2)pi) ?

The solution to expand-sin((k+1/2)pi) is -(-1)^k

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expand-sin((k+1/2)pi)

expand

- sin ((k + \frac{1}{2}) π)

- (- 1)^{k}

Solution steps

- sin ((k + \frac{1}{2}) π)

Expand

(k + \frac{1}{2}) π : πk + \frac{π}{2}

= - sin (πk + \frac{π}{2})

Rewrite using trig identities

= - cos (πk)

Use the basic trigonometric identity:

cos (nπ) = (- 1)^{n}

= - (- 1)^{k}

(x) (\frac{( 96 - 16 x )}{12})^{2}

- 2 (e^{x} + e^{x} x)

\frac{( x + 3 ) ^{4}}{4}

\frac{3 x + 5}{( x + 2 ) ^{2} ( x ^{2} + 2 )}

10 x (2 - ln (x))

What is expand-sin((k+1/2)pi) ?
The solution to expand-sin((k+1/2)pi) is -(-1)^k