What are the solutions to the equation 4x^2-4x-15=0 ?

The solutions to the equation 4x^2-4x-15=0 are x= 5/2 ,x=-3/2

Find the zeros of 4x^2-4x-15=0

The zeros of 4x^2-4x-15=0 are x= 5/2 ,x=-3/2

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4 x^{2} - 4 x - 15 = 0

x = \frac{5}{2}, x = - \frac{3}{2}

Decimal Notation

x = 2.5, x = - 1.5

Solution steps

4 x^{2} - 4 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 ( - 15 )}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 (- 15) = 16

x_{1, 2} = \frac{- ( - 4 ) \pm 16}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 16}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 16}{2 \cdot 4}

x = \frac{- ( - 4 ) + 16}{2 \cdot 4} : \frac{5}{2}

x = \frac{- ( - 4 ) - 16}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - \frac{3}{2}

x^{2} + 10 x = 2 x

\frac{f}{- 7} - 8 = 2

\frac{4}{3 + 6}

2 lo g_{2} (8)

2 x^{2} - 4 x - 8 = 0

What are the solutions to the equation 4x^2-4x-15=0 ?
The solutions to the equation 4x^2-4x-15=0 are x= 5/2 ,x=-3/2
Find the zeros of 4x^2-4x-15=0
The zeros of 4x^2-4x-15=0 are x= 5/2 ,x=-3/2