What is expand 1/((s+2)(s^2+2s+4)) ?

The solution to expand 1/((s+2)(s^2+2s+4)) is 1/(s^3+4s^2+8s+8)

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expand 1/((s+2)(s^2+2s+4))

expand

\frac{1}{( s + 2 ) ( s ^{2} + 2 s + 4 )}

\frac{1}{s ^{3} + 4 s ^{2} + 8 s + 8}

Solution steps

\frac{1}{( s + 2 ) ( s ^{2} + 2 s + 4 )}

Expand

(s + 2) (s^{2} + 2 s + 4) : s^{3} + 4 s^{2} + 8 s + 8

= \frac{1}{s ^{3} + 4 s ^{2} + 8 s + 8}

(1 - ln (x)) (1 + ln (x))

(6 x y^{3}) d x + (4 y^{3} + 9 x^{2} y^{2}) d y

\frac{e ^{x} ( x - 3 ) ^{2}}{( x - 1 ) ^{3}}

\frac{( x + 5 ) ^{2} ( x - 5 ) ^{2}}{2 x}

\frac{2 ( - t ^{2} + 1 )}{( t ^{2} + 1 ) ^{2}}

What is expand 1/((s+2)(s^2+2s+4)) ?
The solution to expand 1/((s+2)(s^2+2s+4)) is 1/(s^3+4s^2+8s+8)